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Sartika Aritonang
news
Commits
f80a93eb
Commit
f80a93eb
authored
May 29, 2020
by
Sartika Aritonang
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intranges.py
stbi/Lib/site-packages/pip/_vendor/idna/intranges.py
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stbi/Lib/site-packages/pip/_vendor/idna/intranges.py
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f80a93eb
"""
Given a list of integers, made up of (hopefully) a small number of long runs
of consecutive integers, compute a representation of the form
((start1, end1), (start2, end2) ...). Then answer the question "was x present
in the original list?" in time O(log(# runs)).
"""
import
bisect
def
intranges_from_list
(
list_
):
"""Represent a list of integers as a sequence of ranges:
((start_0, end_0), (start_1, end_1), ...), such that the original
integers are exactly those x such that start_i <= x < end_i for some i.
Ranges are encoded as single integers (start << 32 | end), not as tuples.
"""
sorted_list
=
sorted
(
list_
)
ranges
=
[]
last_write
=
-
1
for
i
in
range
(
len
(
sorted_list
)):
if
i
+
1
<
len
(
sorted_list
):
if
sorted_list
[
i
]
==
sorted_list
[
i
+
1
]
-
1
:
continue
current_range
=
sorted_list
[
last_write
+
1
:
i
+
1
]
ranges
.
append
(
_encode_range
(
current_range
[
0
],
current_range
[
-
1
]
+
1
))
last_write
=
i
return
tuple
(
ranges
)
def
_encode_range
(
start
,
end
):
return
(
start
<<
32
)
|
end
def
_decode_range
(
r
):
return
(
r
>>
32
),
(
r
&
((
1
<<
32
)
-
1
))
def
intranges_contain
(
int_
,
ranges
):
"""Determine if `int_` falls into one of the ranges in `ranges`."""
tuple_
=
_encode_range
(
int_
,
0
)
pos
=
bisect
.
bisect_left
(
ranges
,
tuple_
)
# we could be immediately ahead of a tuple (start, end)
# with start < int_ <= end
if
pos
>
0
:
left
,
right
=
_decode_range
(
ranges
[
pos
-
1
])
if
left
<=
int_
<
right
:
return
True
# or we could be immediately behind a tuple (int_, end)
if
pos
<
len
(
ranges
):
left
,
_
=
_decode_range
(
ranges
[
pos
])
if
left
==
int_
:
return
True
return
False
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